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A constant force of 20 N is exerted for 10 s on

a 40 kg object initially at rest. The change in
speed of this object will be:

User Keruilin
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1 Answer

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Final answer:

The change in speed of a 40 kg object when a constant force of 20 N is exerted for 10 s would be 5 m/s, using Newton's second law of motion.

Step-by-step explanation:

The change in speed of a 40 kg object when a constant force of 20 N is exerted for 10 s can be calculated using Newton's second law of motion. We can find the acceleration by using the formula acceleration (a) = Force (F) / mass (m). Once we have acceleration, we use the formula change in speed (Δv) = acceleration (a) × time (t) to find the change in speed.

To solve the problem:
1. Calculate the acceleration:
a = F/m = 20 N / 40 kg = 0.5 m/s².

2. Calculate the change in speed:
Δv = a × t = 0.5 m/s² × 10 s = 5 m/s. Therefore, the change in speed of the object will be 5 m/s.

User Matthew Kraus
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