The shorter leg is
![√(5) \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/fz2yt9zlm3clp4acm0lol7o3h8e0fbwrxq.png)
Explanation:
Let the base be x and the perpendicular be y.
It is given that, one leg of a right triangle is twice as long as the other leg,
y = 2x ...(1)
Hypotenuse, H = 5 cm
We can use Pythagoras theorem as follows :
![H^2=B^2+P^2](https://img.qammunity.org/2021/formulas/mathematics/college/wyw1ue5o8aek0c44qx6fnywfk9l2cjsqup.png)
Putting all the values,
![5^2=x^2+(2x)^2\\\\25=x^2+4x^2\\\\25=5x^2\\\\x^2=5\\\\x=√(5)\ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/lvujehks3pq4pgehsypaiqwe5z8dhix8kx.png)
So, the base is
. No, to find the value of y put x in equation (1). So,
![y=2x\\\\=2√(5) \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/s9oyz7kkrjooopbl60j0svn58h661g4ftb.png)
Hence, the measure of the shorter leg is
![√(5) \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/fz2yt9zlm3clp4acm0lol7o3h8e0fbwrxq.png)