Question

Tyson throws a shot put ball weighing 7.26 kg. At a height of 2.1 m above the ground, the mechanical energy of the ball is 172.1 J.

What is the velocity of the ball at the given point?

Answer 1

Step-by-step explanation:

The ball is falling down,

At height of 2.1m, there is both potential and kinetic energy with the ball.

the mechanical energy is 172.1J which will be equal to the sum of kinetic and potential energy.

172.1= Ep + Ek

172.1= mgh + 0.5×m×v^2

172.1 =( 7.26 × 9.81 × 2.1 ) + (0.5 × 7.26 × v^2)

172.1 = 149.6 + 3.63v^2

3.63v^2= 22.5

v^2 = 6.198

v=
`√(6.198)`

v= 2.49

or u can write it 2.5m/s^2