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Put the quadratic into vertex form and state the coordinates of the vertex. y=x^2-2x+3

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Answer:

The vertex form of the quadratic: y = (x - 1)² + 2

Coordinates of vertex: (1, 2)

Explanation:


y=x^2-2x+3\\\\y=x^2-2x+1+2\\\\y=(x-1)^2+2

The vertex form of an equation of the parabola is: f(x) = a(x - h)² + k

where (h, k) is the vertex. So:

x - h = x - 1 ⇒ h = 1

+ k = +2 ⇒ k = 2

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