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What is an equation of the line that passes through the points (5,2) and (-5,-6) PLEASE ANSWER

What is an equation of the line that passes through the points (5,2) and (-5,-6) PLEASE-example-1

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Answer:

y = 4/5 x - 2

Explanation:

Find for slope first:

m = (y2 - y1) / (x2 - x1)

= [(-6) - 2] / [(-5) - 2]

= -8/-10

= 4/5

Solve for b. Use (5, 2)

y = mx + b

2 = 4/5 (5) + b

2 = 20/5 + b

2 = 4 + b

2 - 4 = b

-2 = b

Substitute the value of m and b.

y = mx + b

y = 4/5 x + (-2)

y = 4/5 x - 2

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