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Please help if you know how to do this please

Please help if you know how to do this please-example-1
Please help if you know how to do this please-example-1
Please help if you know how to do this please-example-2
Please help if you know how to do this please-example-3

1 Answer

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Answer:

  • quadrants: III, IV
  • vertex: (0, 0)
  • x-intercepts: (0, 0) -- at the vertex
  • dashed line, shaded inside, opens down

Explanation:

Compared to vertex form ...

y = a(x -h)^2 +k

we find that a=-3, (h, k) = (0, 0). That is, the vertex is (0, 0).

A parabola whose vertex is on the x-axis has that as its only x-intercept. (The x-intercept (vertex) is NOT in the solution set.)

The negative leading coefficient tells you the graph opens downward. The y < ( ) comparison tells you shading is below the boundary line, which is dashed. Below a downward-opening parabola is inside the parabola.

The two offered points are on the x-axis, so not in the solution set.

Please help if you know how to do this please-example-1
User Parixit
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