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. Let the random variable P be the air pressure in a car tire, and assume that P is uniformly distributed between 29 and 34 pounds per square inch (psi). Recall that this means that the density curve for P is a flat, horizontal line at some constant level c above the interval from 29 psi to 34 psi. (a) Find the probability that the pressure of a tire will be above 31.7 psi.

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Answer:

The probability is
P(X >  31.7) = 0.54

Explanation:

From the question we are told that

P is uniformly distributed between
a=  29 and
b=34 pounds per square inch (psi)

Generally the uniform distribution cumulative distribution function is mathematically represented as


F(x ) = &nbsp;\left \{ {{ 0 &nbsp;\\ \ \ \ \ \ &nbsp;x \le a} \atop { (x-a)/(b-a) \ \ \ \ \ \ \ \ a < &nbsp;x < b}} &nbsp;\atop {1 \ \ \ \ \ \ \ \ \ \ \ \ \ x \ge &nbsp;b}} \right.

Generally the probability that the pressure of a tire will be above 31.7 psi


P(X > &nbsp;31.7) = &nbsp;( 31 . 7 &nbsp;- &nbsp;a )/(b-a)

=>
P(X > &nbsp;31.7) = &nbsp;( 31 . 7 &nbsp;- &nbsp;29 )/(34-29)

=>
P(X > &nbsp;31.7) = 0.54

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