Question

g Katie(50 kg) tries the water slide at the county fair. The starting point is 10.0 m above the ground. She starts from the top of the slide at rest. Assuming zero frictional lost, how fast will Katie be traveling at the bottom

Answer 1

v= 14 m/s

Step-by-step explanation:

• Assuming no friction losses, the total mechanical energy must be conserved.
• At the top of the slide, all the energy is gravitational potential energy, as she starts at rest.
• At the bottom of the slide, if we choose this level as our zero reference level for the gravitational potential energy, all the energy will be purely kinetic.
• So, we can write the following equality:
• 
  `\Delta K + \Delta U =0`

⇒ΔK = -ΔU

⇒
`((1)/(2)*m*v^(2)-0) =-(0- m*g*h) = m*g*h`

• Rearranging terms and simplifying we can solve for v, as follows:

`v_(f) = √(2*g*h) =√(2*9.8m/s2*10.0m) = 14 m/s`

• Katie's speed at the bottom of the slide will be 14 m/s.