Point slope form equation: y-y1=m(x-x1)
Where m=slope
Y1 is any y value from a point on the graph
X1 any x value from the same point on the graph
The first thing to do is find the slope
M= (9-7)/(1-0)=2/1=2
Next is to sun in values
the point given is (1,9)
So we put 9 in place of y1 and 1 in place of x1
So the line in point slope form is
Y-9=2(x-1)
Y intercept formula: y=mx+b
The only new letter is b which is the y intercept value (0,b)
The y intercept is the point where x is 0 which the problem says is (0,7)
So, keeping the same slope
The answer is
Y=2x+7
Standard form: Ax+By=C
Where A,B, and C are integers (can’t be fractions)
If you reorder the slope intercept form
You get
-2x+y=7
You have to flip the signs because a needs to be positive
So the answer is
2x-y=-7
2)
When you see something like f(-3)=4
That is saying when x is equal to -3, the whole equation is equal to 4
So f(x)=n
So when x is -3, y is 4 and when x is -1, y is -4
M=(4+4)/(-3+1)=8/-2=-4
Sub in points to find b
4=-4(-3)+b
4=12+b
b=-8
So,
Y=-4x-8
Std form
Move -4x to the left with addition to get
4x+y=-8
Hope that helped!