Answer:
A
Explanation:
if f(x)=3x^2+2x g(x)=‒x^2+4x
f+g=(3x^2+2x)+(‒x^2+4x)
=3x^2‒x^2+4x+2x
=2x^2+6x
f‒g=(3x^2+2x)‒(‒x^2+4x)
=3x^2+2x+x^2‒4x
=3x^2+x^2+2x‒4x
=4x^2‒2x
i hope my answer will be clear to you
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