Question

Please help me out for question 17

Answer 1

Welcome to the other MHN solving classes.

Let's see what to do ......

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Step (1)

EC bisects BED ;

Thus : BEC = CED

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Step (2)

Question told us that CED = 4 x + 1

Thus : BEC = CED = 4 x + 1

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Step (3)

AD is a straight line which means its angle size is equal to 180° degrees.

So :

AEB + BEC + CED = 180

( 11x - 12 ) + ( 4x + 1 ) + ( 4x + 1 ) = 180

11x + 4x + 4x - 12 + 1 + 1 = 180

19x - 10 = 180

Plus sides 10

19x - 10 + 10 = 180 + 10

19x = 190

Divided sides by 19

`(19)/(19)x = (190)/(19) \\`

`x = 10`

So : x = 10°

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Step (4)

AEB = 11x - 12

AEB = 11(10) - 12

AEB = 110 - 12

AEB = 98°

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BEC = CED = 4x + 1

BEC = CED = 4(10) + 1

BEC = CED = 41°

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Step (5)

AEC = AEB + BEC

AEC = 98° + 41°

AEC = 139°

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And we're done.....♥️♥️♥️♥️♥️