Question

The perimeter of a rectangle is 34 m. The length is 2 m more than two times the

width. Find the length and the width of the rectangle.

Answer 1

P(erimeter) = 2L(ength) + 2W(idth).

But it is given that L = 2W+2.

Use this fact in the formula for the perimeter.

P = 2(2W+2) + 2W

P = 4W + 4 + 2W = 6W + 4.

P given as 22M, therefore

22 = 6W + 4

Subtract 4 from both sides to get 18 = 6W

Divide both sides by 6 to get W(idth) = 18/6 = 3M

L = 2W + 2 = 2*3 + 2 = 8M

P = 2*8 + 2*3 = 16+6 = 22