Question

In a survey of 439 teenagers in the US, 14% said that they worked during their summer vacation. a) What is the Margin of Error for this sample proportion

Answer 1

`0.0166`

Explanation:

Let the sample proportion be
`\hat{p}=0.14` and the sample size be
`n=439`:

`\displaystyle \text{Margin of Error}=\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\\\\\text{Margin of Error}=\sqrt{(0.14(1-0.14))/(439)}\\\\\text{Margin of Error}=\pm0.0166`