Question

X^2-10x+27 in the form (x-a)^2+B​

Answer 1

(x-5)^2+2

Explanation:

To convert between standard and vertex form, you have to complete the square (which, as a reminder, (a+b)^2 = a^2+2ab+b^2).

Since a^2 is x^2, and 2ab is -10x, then b must be -5, so b^2 is 25. Therefore, we add and subtract 25 from the expression:

(x-10x+25)+27-25

Then, we can make (x-10x+25) to (x-5)^2:

(x-5)^2+2