Answer:
1. 14 moles of NH3 were produced.
2. 7 moles of CO2 were produced.
3. 7 moles of H2O were produced.
Step-by-step explanation:
We'll begin by writing a balanced equation for the decomposition of ammonium carbonate, (NH4)2CO3.
This is illustrated below:
(NH4)2CO3(s) —> NH3(g) + CO2(g) + H2O(g)
There are 2 atoms of N on the left side and 1 atom on the right side. It can be balance by putting 2 in front of NH3 as shown below:
(NH4)2CO3(s) —> 2NH3(g) + CO2(g) + H2O(g)
Now the equation is balanced.
From the balanced equation above,
1 mole of (NH4)2CO3 decompose to produce 2 moles of NH3, 1 mole of CO2 and 1 mole of H2O.
1. Determination of the number of mole of NH3 produced.
From the balanced equation above,
1 mole of (NH4)2CO3 decompose to produce 2 moles of NH3.
Therefore, 7 moles of (NH4)2CO3 will decompose to produce = 7 × 2 = 14 moles of NH3.
Therefore, 14 moles of NH3 were produced.
2. Determination of the number of mole CO2 produced.
From the balanced equation above,
1 mole of (NH4)2CO3 decompose to produce 1 mole of CO2.
Therefore, 7 moles of (NH4)2CO3 will also decompose to produce 7 moles of CO2.
Therefore, 7 moles of CO2 were produced.
3. Determination of the number of mole of H2O produced.
From the balanced equation above,
1 mole of (NH4)2CO3 decompose to produce 1 mole of H2O.
Therefore, 7 moles of (NH4)2CO3 will also decompose to produce 7 moles of H2O.
Therefore, 7 moles of H2O were produced.