Question

A mass (m = 30 g) falls onto a spring (k = 7.3 N/m) from a height (h = 25 cm). The spring compresses an additional amount x before temporarily coming to a stop. What is the value of x?

Answer 1

x₁ = 0.1878 m

Step-by-step explanation:

For this exercise we will use conservation of energy

starting point. Highest point

Em₀ = U = m g h

final point. Lowest point with fully compressed spring

Em_f = K_e + U

Em_f = ½ K x² + m g x

energy is conserved

Em₀ = Em_f

m g h = ½ K x² + m g x

½ K x² + mg (x- h) = 0

let's substitute

½ 7.3 x² + 0.030 9.8 (x- 0.25) = 0

3.65 x² + 0.294 (x- 0.25) = 0

x² + 0.080548 (x- 0.25) = 0

x² - 0.020137 + 0.080548 x = 0

x² + 0.080548 x - 0.020137 = 0

let's solve the quadratic equation

x = [0.080548 ±√ (0.080548² + 4 0.020137)] / 2

x = [0.080548 ± 0.29502] / 2

x₁ = 0.1878 m

x₂ = -0.1072 m

These are the compression and extension displacement of the spring