Answer:
The school is at displacement of 1 mile towards South from the home.
Explanation:
Let the origin, O, represents the location of the school.
Now, observe the attached figure for all the displacements as:
She drove 5 miles East to shore ( to point A)
So, OA=5 miles.
Then she drove 2 miles North to Pelican's ( to point B)
So, AB=2 miles.
Then she drove 5 miles South to her friend's house ( to point C)
So, BC=5 miles.
Then she drove 7 miles West, to point D,
So, CD=7 miles.
Then she drove 4 miles North, to point E,
So, DE=4 miles.
Lastly, she drove 2 miles East, to reach home (the point F)
So, EF=2 miles.
Now computing the displacements in each direction.
The displacements in the East direction=OA+EF= 5+2= 7 miles
The displacements in the West direction =CD= 7 miles
As East and West are opposite to east other, so net displacements in the East direction = 7+(-7)=0, i.e the final point F ( home) is on the vertical axis as shown.
The displacements in the North direction=AB+DE= 2+4= 6 miles
The displacements in the South direction=BC=5 miles
As North and South are opposite to east other, so net displacements in the North direction = 6+(-5)= 1 miles which means final point F ( home) is located at 1 mile towards North from the school.
Hence, the school is at displacement of 1 mile towards South from the home.