Question

The sides of a triangle are as follows:

AB = 10 in
BC = 14 in
AC = 8 in
Order the angles of the triangle from smallest to biggest.
<B, <A, <C
<B, <C,<A
<A, <C, <B
<A, <B, C​

Answer 1

The order of the angles of Δ ABC from smallest to biggest is

∠B < ∠C < ∠A ⇒ B

Explanation:

There is a fact about a triangle

• The longest side is opposite to the greatest angle

• The shortest side is opposite to the smallest angle

Let us use this fact to solve our question

In Δ ABC

∵ AB = 10 inches

∵ BC = 14 inches

∵ AC = 8 inches

→ Find the longest and shortest sides

∴ BC is the longest side

∴ AC is the shortest side

∵ BC is opposite to ∠A

∴ ∠A is the biggest angle in measure

∵ AC is opposite to ∠B

∴ ∠B is the smallest angle in measure

∴ The order of the angles of Δ ABC from smallest to biggest is

∠B < ∠C < ∠A