Question

Find the area of a sector in a circle with radius 2 inches, with an angle 0= pie/3

Answer 1

`\boxed{\sf (2\pi )/(3) \ in^2}`

Step-by-step explanation:

`\sf Formula \ for \ area \ of \ sector = (\theta)/(2\pi ) \ x \ \pi r^2`

Here given following:

• radius: 2 inch

• angle(∅): π/3

Solve for area:

`\rightarrow \sf (\pi /3)/(2\pi ) \ x \ \pi \ x \ (2)^2`

`\rightarrow \sf (\pi /3)/(2\pi ) \ x \ 4\pi`

`\rightarrow \sf (\pi )/(3) \ x \ 2`

`\rightarrow \sf (2\pi )/(3)`