140k views
5 votes
Solve 2sin (3x) – 1 = 0 on the interval [0, 2π).

User John Resig
by
3.2k points

1 Answer

10 votes

Answer:

Explanation:

Here uu go

Solve 2sin (3x) – 1 = 0 on the interval [0, 2π).-example-1
User Zerocog
by
3.7k points