Question

A body of rotational inertia 1.0 kg m2 is acted upon by a torque of 2.0 Nm. The angular acceleration of the body will be

Answer 1

The angular acceleration is 2 rad/s².

Step-by-step explanation:

Given that,

Rotational inertia = 1.0 kg m²

Torque = 2.0 Nm

We need to calculate the angular acceleration

Using formula of torque

`\tau=I\alpha`

`\alpha=(\tau)/(I)`

Where, I = moment of inertia

`\tau` = torque

Put the value into the formula

`\alpha=(2.0)/(1.0)`

`\alpha=2\ rad/s^2`

Hence, The angular acceleration is 2 rad/s².