Maximum area = 2ab
from ellipse eqn
x^2 + 4y^2 = 49
(x+4y)^2= 49
underoot both sides
x + 4y = 7 ---eqn1
from
(ab)^2 = (ax + by)^2
ab= ax + by
compare to eqn1
ab=7
then, area of the largest triangle will be 14 units.
i hope it's ryt
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