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An acid-base reaction of (r)-sec-butylamine with a racemic mixture of 2-phenylpropanoic acid forms two products having different melting points and somewhat different solubilities. Draw the structure of these two products. How are the two products related? Be sure to answer all parts.

User Tjdett
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Answer:

See explanation

Step-by-step explanation:

When an optically active compound reacts with a racemic mixture, two different products appear .

Hence, when (R)-sec-butylamine reacts with a racemic mixture of 2-phenylpropanoic acid as shown in the image attached.

Enantiomers are optical isomers which are mirror images of each other. The image attached was obtained from Bartleby.

An acid-base reaction of (r)-sec-butylamine with a racemic mixture of 2-phenylpropanoic-example-1
User Mitul Bhadeshiya
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