Question

Bridget went fishing with her dad. Bridget Bridget caught the first fish of the day, another was 2 more than 3 times the weight of the first fish, the next was 1/2 the weight of the first fish, and the last was 3/5 the weight of the first fish.

Bridget's dad caught four fish. the first fish he caught weighed 2 more than 3 times a weight of the first fish caught that day. one fish weighed 4/5 in the weight of the first fish caught that day, one weighed 4 more than 2 times the weight of the first fish caught that day, and the last one weighed 1/2 the weight of the first caught that day.

if all the fish Bridget caught have the same total weight as the fish her dad caught, then the first fish Bridget caught weighed ____ ounces in the first fish her dad caught weighed ____ ounces.​

Answer 1

Bridget's first fish =f = 5 ounces

Bridget's dad first fish weighs 17 ounces

Explanation:

Solution:

Bridget's fishes:

f ounces

2f ounces

3f+2 ounces

1/2f ounces

3/5f ounces

Total= f +2f + (3f+2) + 1/2f +3/5f

=3f + 3f + 2 + 5f+6f/10

=6f + 2 + 11f/10

=60f+11f/10 +2

=71/10f +2

Bridget's dad fishes

3f+2

4/5f

2f+4

1/2f

Total =(3f+2) + (2f+4) + 4/5f +1/2f

=3f+2+2f+4 + 8f+5f/10

=5f + 6 + 13/10f

= 50f+13f/10 + 6

=63/10f +6

Equate the total weight

71/10f +2=63/10f +6

Collect like terms

71/10f - 63/10f =6-2

71f-63f/10 = 4

8f/10=4

Cross product

8f=40

Divide both sides by 8

f=5

Bridget's first fish =f = 5 ounces

Bridget's dad first fish = 3f +2

=3(5)+2

=15+2

=17 ounces

Bridget's dad first fish weighs 17 ounces