Answer:
E_aprox = 1.003 E_real
Step-by-step explanation:
In this exercise we are given the expression for the electric field of a dipole in the axis direction of the dipole
E_real = k 2q d / √(z² + d²)³
I think your equation has some errors.
In this case they indicate that d is the separation of the charges of the dipole
in the case of z »d this equations approximates
E_aprox = k 2q d/ z³
calculate the value for the two cases
E_real = k2q d / √[ ((23d)² + d²)³]
E_real = k2q d / d³ 12201
E_real = k2q 1/12201 d²
E_aprox = k2q d / (23.00d)³
E_aprox = k2q 1/12167 d²
the error between these quantities is
E_aprox / E_real = 12201 d² / 12167 d²
E_aprox / E_real = 1.003
E_aprox = 1.003 E_real