Question

A student increases the temperature of a 300 cm^3 balloon from 300 K to 600 K. what will the new volume of the ballon be​

Answer 1

600 cm^3

Step-by-step explanation:

V1/T1 = V2/T2

300/300 = V2 * 600

V2 = 600 cm^3

Answer 2

This is an exercise in the law of Jackes Alejandro Charles.

To start solving this exercise, we obtain the following data:

Data:

• V₁ = 300 cm³
• T₁ = 300 k
• V₂ = ¿?
• T₂ = 600 km

If the temperature doubles the volume doubles; If the temperature is halved, the volume is halved.

"Mathematically this law expresses itself"

`\bf{(V_(1))/(T_(1))=(V_(2))/(T_(2)) \qquad \ in \ where: }`

• V₁= Initial volume
• V₂ = Final volume
• T₁ = Initial temperature
• T₂ = Final temperature

We can also express it: V₁T₂=V₂T₁

Clear for "V₂":

`\bf{V_(2)=(V_(1)T_(2))/(T_(1)) \ \ \to \ \ \ Clear \ formula }`

We clear our data in the formula:

`\bf{V_(2)=\frac{(300 \ cm^(3))(600 \\ot{k}) }{300 \\ot{K}} }`

`\bf{V_(2)=600 \ cm^(3) }`

The new volume of the balloon will be 600 cm³.

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