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Let g(x) = 2x and h(x) = x2 + 4. Evaluate (h ∘ g)(−2)

1 Answer

3 votes

Answer:


(h(g))(-2)=-32

Explanation:

Evaluate h ⋅ g

Replace the function designators in h ⋅ g with the actual functions.


(h(g))(-2)=(x^(2) +4)(2x)


=2x^(2)x+8x

Multiply
x^(2) by x by adding the exponents.


=2x^(3)+8x

Evaluate h ⋅ g at −2.


=2(-2)^(3)+8(-2)

Simplify


=-16-16

subtract 16 from -16


(h(g))(-2)=-32

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