335,395 views
26 votes
26 votes
A= 4 π r ^2 make r the subject

User Tammye
by
2.8k points

1 Answer

7 votes
7 votes

Hello !

Answer:


\boxed{\sf r = \sqrt{(A)/(4\pi)}}

Explanation:

We will isolate r and express it in terms of A, 4, and π.


\\

Given equality:


\sf A = 4\pi r^2


\\

Divide both sides of the equality by 4π.


\sf (A)/(4\pi) = (4 \pi r^2)/(4\pi) \\ \\ \sf (A)/(4 \pi) = r^2

Take the square root.


\sf \sqrt{(A)/(4\pi)}= √(r^2) \\ \\ \implies \boxed{\sf r = \sqrt{(A)/(4\pi)}}

Have a nice day ;)

User Guruprasad GV
by
3.3k points