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Find the width of a rectangular wall if the perimeter is 148 feet and the width is two more than seven times the length.

User Yina
by
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1 Answer

5 votes

Answer:

Explanation:

Perimeter of a rectangular wall P = 2L+2W

L is the length of the wall

W is the width

Given

P = 148feet

If the width is two more than seven times the length, this is represented as

W = 7L+2

Substitute W = 7L+2 into the formula above

P = 2L + 2(7L+2)

P = 2L +14L+4

P == 16L+4

148 = 16L+4

16L = 148-4

16L = 144

L = 144/16

L = 9

To get the width

W = 7L+2

W = 7(9)+2

W = 63+2

W = 65feet

Hence the width of the rectangular wall is 65feet

User Navneet Kumar
by
5.2k points
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