Answer:
CI = (3.462, 4.138)
Explanation:
We are given;
Sample mean; x¯ = 3.8
Sample standard deviation; s = 1.19
Sample size; n = 50
DF = n - 1 = 50 - 1 = 49
Confidence level; CL = 95%
Significance level = (1 - 0.95)/2 = 0.025
Now,from the table attached using DF = 49, significance level = 0.025, one tail and by interpolation, we have; t = 2.01
Now, formula for confidence interval is;
CI = x¯ ± t(s/√n)
CI = 3.8 ± 2.01(1.19/√50)
CI = 3.8 ± 0.338
CI = (3.8 - 0.338, 3.8 + 0.338)
CI = (3.462, 4.138)