Question

Determine the measure of ∠Q, rounded to the nearest tenth of a degree.
images attached.

Answer 1

D

Explanation:

Using the Sine rule in Δ QRS , that is

`(q)/(sinQ)` =
`(r)/(sinR)` , that is

`(15)/(sinQ)` =
`(12)/(sin50.1)` ( cross- multiply )

12× sinQ = 15 × sin50.1° ( divide both sides by 12 )

sinQ =
`(15sin50.1)/(12)` , thus

Q =
`sin^(-1)` (
`(15sin50.1)/(12)` ) ≈ 73.5° ( to the nearest tenth )