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What is the equation of the line that is parallel to the the line y-1 =4 (x+3) and passes through th point (4,32)
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What is the equation of the line that is parallel to the the line y-1 =4 (x+3) and passes through th point (4,32)

User Sherida
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I used Symbolab to calculate my answer. It is y=4x + 16.

Calculation of slope: y-1=4(x+3) m= 4 and b=16
User Louis Kottmann
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