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Bender Electronics buys keyboards for its computers from another company. The keyboards are received in shipments of 100 boxes, each box containing 20 keyboards. The quality control department at Bender Electronics first randomly selects one box from each shipment and then randomly selects 5 key boards from that box. The shipment is accepted if not more than 1 of the 5 keyboards is defective. The quality control inspector at Bender Electronics selected a box from a recently received shipment of keyboards. Unknown to the inspector, this box contains 6 defective keyboards.

Round your answers to four decimal places.
a. What is the probability that this shipment will be accepted?
P(shipment accepted)=
b. What is the probability that this shipment will not be accepted?
P(shipment not accepted)=

User Radnan
by
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1 Answer

4 votes

Answer:

a


P(shipment\ accepted) =0.6337\

b


P(shipment\ not\ accepted)= 0.3663

Explanation:

from the question we are told that

The number of boxes N = 100

The number of keyboard in each box is k = 20

The sample size is n = 5

Generally the number of ways of selecting 1 keyboard from the 5 selected keyboard is mathematically represented as


G  =  \ ^(5)C_1

Here C stands for combination (Hence in the question we will be making use of the combination functionality in our calculator )

Generally the number of ways of selecting 0 keyboard from the 5 selected keyboard is mathematically represented as


H  =  \ ^(5)C_0

Generally the number of ways of selecting 5 keyboard from the 20 keyboards is mathematically represented as


F  =  \ ^(20)C_5

Generally the number of ways of selecting 5 keyboard from the 15 keyboards is mathematically represented as


W  =  \ ^(15)C_5

Generally the number of ways of selecting 5 keyboard from the 15 keyboards is mathematically represented as


V  =  \ ^(15)C_4

Generally the probability that a shipment will be accepted is mathematically represented as

Probability of 0 defect out of 5 + Probability of 1 defect out of 5

Now

Probability of 0 defect out of 5 is mathematically represented as


P(A_1) =  (H*W )/( F)

=>
P(A_1) =  (1 *3003 )/( 15504)

=>
P(A_1) =  0.1937

And Probability of 1 defect out of 5 is mathematically represented as


P(A_2) =  ( G * V)/( F)

=>
P(A_2) =  ( 5 * 1365)/(15504)

=>
P(A_2) =  0.440

Generally the probability that a shipment will be accepted is mathematically represented as


P(shipment\ accepted) =0.1937 +  0.440

=>
P(shipment\ accepted) =0.6337

Generally the probability that this shipment will not be accepted is mathematically represented as


P(shipment\ not\ accepted)= 1 -P(shipment \ accepted)


P(shipment\ not\ accepted)= 1 - 0.6337


P(shipment\ not\ accepted)= 0.3663

User Biranchi
by
5.6k points
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