Answer: The students can be divided into 7 groups.
Each group will have 3 boys and 8 girls.
Explanation:
There are 21 boys and 56 girls.
To divide them so that each group has the same number of both boys and girls.
We find GCD(21,56).
21 = 3 x 7
56 = 2 x 2 x 2 x 7
GCD (21,56) = 7
So, the students can be divided into 7 groups.
Number of girls in each group =
![(56)/(7)=8](https://img.qammunity.org/2021/formulas/mathematics/high-school/2xoqcftj2y67dxkpugm6je5mfinw66k9sk.png)
Number of boys in each group =
![(21)/(7)=3](https://img.qammunity.org/2021/formulas/mathematics/high-school/si13mtya79xcjlapa1l79tgyod1574vqvo.png)
So, each group will have 3 boys and 8 girls.