Answer:
![43.1 ^(\circ)F](https://img.qammunity.org/2021/formulas/mathematics/high-school/m4pkzeb1cglon5rkbfuywclhc0fahdydy9.png)
Explanation:
Give that for every 1000 feet increase in the height there is a drop of
in temperature.
So, the rate of temperature drop with respect to height, R = 1.7/1000
.
If the change in height is
![\Deltah](https://img.qammunity.org/2021/formulas/mathematics/high-school/64v5ap0l340e5b22j2ot5bvj9997z7axhh.png)
feet, the temperature drop,
![\Delta T= \Delta h R \;^(\circ)F\cdots(i)](https://img.qammunity.org/2021/formulas/mathematics/high-school/aphr5fr7jdtlc9pa0da30afyrtapyzrzqg.png)
The temperature on the ground is 49.9
.
At the ground, the height is 0, so the change in height, \Delta h when the plane reaches an altitude of 4,000 feet, is
\Delta h =4000-0=4000 feet
Now, from equation (i), the temperature drop
![\Delta T= 4000 * \frac {1.7}{1000}=6.8\;^(\circ)F.](https://img.qammunity.org/2021/formulas/mathematics/high-school/sbzs2p5v0fwo0m6sy4w4q593no103ctknp.png)
Hence, the temperature at an altitude of 4000 feet
.