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Solve the following system of equations algebraically:

y = 4x^2 + 17x + 14
y = 2x + 5​

1 Answer

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Answer:

When x = -3 y = -1

When x = -3/4 y = 7/2

Explanation:

y = 4x^2 + 17x + 14

y = 2x + 5​

Set each equation equal to each other

4x^2 + 17x + 14 = 2x + 5​

Subtract 2x from each side

4x^2 + 17x-2x + 14 = 2x-2x + 5​

4x^2 + 15x + 14 = 5​

Subtract 5 from each side

4x^2 + 15x + 14-5 = 5​-5

4x^2 + 15x +9 = 0

Factor

(4x+3) ( x+3) =0

Using the zero product property

4x+3 =0 x+3 =0

4x = -3 x=-3

x = -3/4 x=-3

Now we need to find y for each x

x =-3 y = 2x+5 =2(-3)+5 = -6+5 = -1

When x = -3 y = -1

x = -3/4 y = 2(-3/4) +5 = -3/2 +5 = 7/2

When x = -3/4 y = 7/2

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