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3.58 x 1023 molecules of propane C8H8 would occupy how much space at STP
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3.58 x 1023 molecules of propane C8H8 would occupy how much space at STP

User Triazotan
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Answer: At STP, a mole of gas takes up 22.4 Liters. The 22.4 Liters/mole quantity can be derived from the Ideal Gas Law, PV = nRT, plugging in STP conditions for P and T, and solving for V/n, which gets 22.4 Liters/mole.

Step-by-step explanation:

User Harpun
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