Question

Pls answer its 2 in the morning I’m tryna get sleeppp

4
Mis the midpoint of CD. Given
the coordinates of one endpoint
C(10,-5) and the midpoint
M(4,0), find the coordinates of
the other endpoint D of CD.
a) (7.)
b) (-2)
c) (-2,5)
d) (7,5)
e) (1,1)

Answer 1

(-2,5)

Explanation:

use formula: m= (
`(x^(1)+x^(2) )/(2) , (y^(1)+y^(2) )/(2)`)

midpoint(m) equals (4,0) and C is (10,-5)

C represents
`(x^(1) ,y^(1))` and other endpoint D represents
`(x^(2), y^(2) )` so:

(4,0) =
`((10+x^(2) )/(2) , (-5+y^(2) )/(2) )`

4 =
`(10+x^(2) )/(2)`

`4*2 = ((10+x^(2) )/(2) )2` Get rid of 2 by multiplying both sides by 2

8 =
`10 + x^(2)` Subtract both sides by 10

`x^(2) = -2` x coordinate of D = -2

To find y coordinate of D:

0 =
`(-5+y^(2) )/(2)` Get rid of 2 by multiply both sides by 2

0 =
`-5 + y^(2)` Add both sides by 5

`y^(2) = 5` y coordinate of D = 5

So if x-coordinate of D= -2 and y-coordinate of D=5, the coordinates for D is (-2,5)