Question

CHEMISTRY! 50 POINTS! What is the original pressure of 20.0L of compressed gas if the pressure changes to 560.0mmHg when the volume is decreased to 15700mL?

Answer 1

The answer is 439.60 mmHg

Step-by-step explanation:

To find the original pressure we use the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the original pressure

`P_1 = (P_2V_2)/(V_1) \\`

From the question

V1 = 20 L = 20,000 mL

P2 = 560.0mmHg

V2 = 15700mL

We have

`P_1 = (560 * 15700)/(20000) = (8792000)/(20000) = (2198)/(5 ) \\`

We have the final answer as

439.60 mmHg

Hope this helps you