Question

PLEASE HELP!!!

what was the volume of air that has a volume of 6.00L at 120870 Pa, if the original pressure was 250020 Pa?

Answer 1

The answer is 2.90 L

Step-by-step explanation:

In order to find the original pressure , we use the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the original volume

`V_1 = (P_2V_2)/(P_1) \\`

From the question

P1 = 250020 Pa

P2 = 120870 Pa

V2 = 6 L

We have

`V_1 = (120870 * 6)/(250020) = (725220)/(250020) \\ = 2.90064794...`

We have the final answer as

2.90 L

Hope this helps you