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Write an equation of a line passing through point p(4, 0) that is parallel to the line -x+2y=12​

1 Answer

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Answer:

y =
(1)/(2)x - 2

Explanation:

Given parameters:

Coordinates = p(4,0)

Equation of the line -x+2y=12​

Solution:

A line parallel to the given line will have the same slope as it is;

-x+2y=12​

2y = x + 12

y =
(1)/(2)x +
(12)/(2)

Since this conforms to y = mx + c where;

x and y are the coordinates

m is the slope

c is the intercept

Our slope is
(1)/(2)

The equation of the line is

y = mx + c

let us find c;

c = y - mx

c = 0 - (
(1)/(2) x 4)

c = -2

Now the equation of the line parallel to the line given is;

y =
(1)/(2)x - 2

User Minikomi
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