F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(3) = 3(3)^2 + 1 = 27 + 1 = 28
G(4) = 2(4) - 3 = 8 - 3 = 5
2H(5) = 2(5) = 10
F(3) + G(4) - 2H(5) = 28 + 5 - 10
F(3) + G(4) - 2H(5) = 23
question 2
Given: F(x) = 5x - 6 and G(x) = x - 4
(FoG) (x) = F(G(x)) = 5(x-4) - 6
= 5x - 20 - 6
= 5x - 26
Inverse
x = 5y - 26
5y = x + 26
y = x/5 + 26/5
So
(FoG) -1 (x) = x/5 + 26/5