Question

Help me pls I need it solve in 25min​

Answer 1

a) Make x=0
y= 15
M= (0,15)
b) Make y=0 and solve the quadratic equation
(x+3)(x-5)=0
x=-3, y=0
x=5, y=0
c) -b/2a
Max point coordinate= (1,16)

Answer 2

See below ~

Explanation:

(a) To find y-intercept :

• y = -x² + 2x + 15
• y = -(0)² + 2(0) + 15
• y = 15
• M is : (0, 15)

(b) Finding x-intercepts :

• 0 = -x² + 2x + 15
• -x² + 5x - 3x + 15 = 0
• x(-x + 5) + 3(-x + 5) = 0
• (x + 3)(-x + 5) = 0
• x + 3 = 0 ⇒ x = -3
• -x + 5 = 0 ⇒ x = 5
• P and Q are : (-3, 0) and (5, 0)

(C) Finding vertex :

• Vertex is (h, k)
• h = -b/2a = -2/2(-1) = 1
• k = -(1)² + 2(1) + 15
• k = -1 + 2 + 15
• k = 16
• The maximum point is : (1, 16)