Question

5. What mass of water can be heated from 15.0°C to 40.0" with 925 Joules 2 points of heat?

Answer 1

Mass of water = 8.84 g

Further explanation

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

c of water = 4.182 J / g ° C

Q = 925 J

mass of water :

`\tt Q=m.c.\Delta T\\\\925=m* 4.182* (40-15)\\\\m=8.84~g`