Question

B. Show that tan(45+ A) = 1+ tan A 1- tan A​

Answer 1

See below ~

Explanation:

Solving :

Taking the LHS :

• tan (45 + A)

Formula :

• tan (x + y) = tan x + tan y / 1 - (tan x)(tan y)

Solving :

• tan (45 + A) = tan 45° + tan A / 1 - (tan 45°)(tan A)
• tan (45 + A) = 1 + tan A / 1 - tan A (because tan 45° = 1)
• Equal to the RHS

∴ Hence, it is proved √

Answer 2

LHS = tan(45° - A)

`=(tan45-tanA)/(1+tan45tanA)`

`=(1-tanA)/(1+tanA) =RHS`