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4 votes
What is the percent error for the experiment if the actual density is

2.49g/mL but the experimental value is 1.47 g/mL?

User ComDubh
by
5.2k points

1 Answer

7 votes

Answer:

The answer is 40.96%

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula


P(\%) = (error)/(actual \: \: number) * 100\% \\

From the question

actual density = 2.49g/mL

error = 2.49 - 1.47 = 1.02

We have


p(\%) = (1.02)/(2.49) * 100 \\ = 40.96385542...

We have the final answer as

40.96 %

Hope this helps you

User Jolson Da Costa
by
5.3k points