Answer:
i) 3
ii) 5
Explanation:
Let H be the set of students who play Hokey
V be the set of students who play Volleyball
S be the set of students who play Soccer
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card(volleyball only) = card(V) - [card(V∩H∩S) + card(V∩H only) + card(V∩S only)]
= 73 - [50 + (58-50) + (62-50)]
= 73 - [50 + 8 + 12]
= 73 - 70
= 3
………………………………………………
Card(Hokey only) = 100 - [3 + 8 + 50 + 10 + 12 + 12]
= 100 - 95
= 5
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Note :
A Venn diagram might be helpful in such case.