Question

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 lb), and a music player (0.4 lb). Using the inequality x Less than or equal to 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed? Explain.

Answer 1

The total weight of the items is 1.25 + 0.25 + 0.6 + 0.4 = 2.5 lb. 2.5 is 0.25 greater than 2.25, so not all the items can be added. If Li leaves out the extra game, which weighs 0.25 lb, she’d have the greatest possible weight allowed.

Explanation:

Answer 2

She will leave an extra video game which weighs 0.25lb

Explanation:

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 lb), and a music player (0.4 lb). Using the inequality x ≤ 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed?

Solution:

Weight of the items

hairdryer = 1.25 lb

hand-held video game = 0.6 lb

an extra video game = 0.25 lb music player = 0.4 lb

The total weight of the items

= 1.25lb + 0.25lb + 0.6lb + 0.4lb

= 2.5 lb.

Total weight - required weight

= 2.5lb - 2.25lb

= 0.25lb

2.5lb is 0.25lb greater than 2.25lb

Therefore, not all items can be added.

She has to leave out an item equivalent to 0.25lb

Item equivalent to 0.25lb is the extra video game

If Li leaves out the extra game, which weighs 0.25 lb, she’d have the maximum weight allowed.