Answer:
please find the solution:
Explanation:
please find the correct question:
Given value:
![\to 4x \equiv 2(mod\ n) \ \ \ \ \ \ \ \ \ \ \ \ _(where) \ \ n=6\\\\\to 4x \equiv 2 (mod 6)](https://img.qammunity.org/2021/formulas/mathematics/college/h9kv0cls22876k2ivtzhapfhg4v1nunxbq.png)
should be divisible by 6 we are also given that
and start with x = 0
=-2 which is not divisible by 6
x= 1
= 2 not divisilble by 6
x= 2
= 6 which is divisible by 6
x=3
= 10 not divisible by 6
x=4
= 14 not divisible by 6
x=5
= 18 which is divisible by 6
so such x are x = 2 and x = 5