80.6k views
2 votes
If four players on a basketball team are 6'1", 6'2",

6'3", and 6'5", how tall would a fifth player have to
be so that the team average (arithmetic mean) would
be 6'4"?
A. 6'9"
B. 6'8"
C. 6'6"
D. 6'5"
E. 6'4"

User Malk
by
6.5k points

1 Answer

6 votes
A 6’9 you add up the heights in inches
6’1 = 73 inches
6’2 = 74 inches
6’3 = 75 inches
6’5 = 77 inches
6’9 = 81 inches
Add them together you get 380 then divide 380 by 5 (one for every height) you get 76 and 76 inches is equal to 6’4
User GOK
by
6.6k points
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